![]() ![]() The original Linked list will be passed to the function to reverse. Reverse the Linked List without Recursion in C/C++ Time Complexity for this program will be O(n) as we are calling recursion at once for each node. After running this program element will print Linked List in reverse order as 30 20 10. ![]() Display Linked List in reverse order using recursionĮlements in the Linked List are 10, 20, 30. PNode3 = (struct node *)malloc(sizeof(struct node *)) PNode2 = (struct node *)malloc(sizeof(struct node *)) PNode1 = (struct node *)malloc(sizeof(struct node *)) call recursive function for next node (p->pLink)ĭifficulty Level: Moderate if you are familiar with Linked List and Recursion.Ĭ Program to Print Linked List in Reversed Order using Recursion.Prerequisite: Recursion in C Explained with ExampleĪlgorithm: Here we need head recursion. Print Linked List in Reverse Order using Recursion in C In this programming tutorial, we are reversing linked list with and without recursion. Reverse Singly Linked List Implementation (Logic):īasically, there are two approaches to reverse the linked list. We have also solved the same problem in Java as well. In this post, we see how to reverse the elements of the linked list using three-pointers in C/C++. In the previous post, we have seen the implementation of the Linked List in C. Prerequisite: How to create Linked List in C/C++? Each node has a data variable to store data and a node pointer to point next node in the linked list. Reverse a Linked List in groups of given size.The linked list is the crucial data structure that contains a list of the nodes. Reverse a Linked List from position M to N. Pointer which will be the head of the reversed list.Ĭan we reverse a Linked List in less than O(n) time? Impossible right? What if the Linked List is doubly Linked List.Ĭan we use Stack for reversing the Linked List? If Yes, what will be the Complexity? Is not equal to NULL and do the following update in every step of the iteration: We will iterate over the linked list untill Space Complexity = O(n), for recursion stack space. Time Complexity = O(n), where n is the length of the Linked List ListNode restReversedPart= reverseList(head.next) If(head = NULL || head.next = NULL) then return Null. Return the head pointer of the reversed list i.e. So, do the following operations to ensure this: Recursively reverse the linked list with (n-1) nodes and return the head pointer of this part i.e.īut for the complete reversal of the list, the head should be the last node. We can divide the linked list with n nodes into two parts: head and the rest of the linked list with n-1 nodes This idea can be implemented in two ways → We will follow the same approach for all the node and finally our new reversed Linked List will be ready. The idea here is to de-link a node from its previous node and add the previous node in front of the current node. What if only one node is given in input?( No, just return the head of the reversed Linked List.) Possible follow-up questions to ask the interviewer:ĭo we have to print the Linked List in reverse order?( This should be done by de-linking the nodes and again linking it in reverse order. After the reversal, The head data should become the last data element pointing to null. Given a linked list pointed by a head node as input, your task is to reverse the linked list. Asked in: Microsoft, MakeMyTrip, Adobe, Amazon ![]()
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